Gorton_Tubster
Well-Known Member
- Joined
- 2 Apr 2012
- Messages
- 18,882
- Location
- Riding the blue tidal wave.
- Team supported
- Manchester City
Right I'm off shopping, this better be sorted by the time I'm back.
small? ;)There IS a small chance Tolm was just on the Bucky again.
Any more info on this mate? Him being unhappy makes me extremely happyHarris isnt happy , make of that what you will
take my missus with you, it will definitely be sorted by the time shes done.Right I'm off shopping, this better be sorted by the time I'm back.
Top tip. Jump to the last page and read backwards. Doesn’t take long to realise nothing has happened.FFS, stepped away to take the dog for a walk and ANOTHER 7 pages, am never gonna get to the end!!!
View attachment 148992
Tell me more.Harris isnt happy , make of that what you will
Likely to be almost daily now until it is released I would think.We’ll do it all over again next Friday. Same time and same place .
All that from an Elbow video, amazing.I see it as he heard good news on the charges and it will be a good day when announced. Possibly draft reports gone out to the parties. I don't think a public announcement will be today though.
It would appear so.Wait, people actually expected the 115 decision would just be announced out of the blue by Pep at a pre-match press conference??
No, nobody was expecting that.Wait, people actually expected the 115 decision would just be announced out of the blue by Pep at a pre-match press conference??
Pep’s announcement did come out of the blue at a Pellegrini presser. Quite hilarious to see everyone scrambling around suddenlyWait, people actually expected the 115 decision would just be announced out of the blue by Pep at a pre-match press conference??
k = 1The world's hardest maths equation.
Find x, y, and z such that x³+y³+z³=k, for each k from one to 115.
Richards Masters got it wrong.
Pep’s announcement did come out of the blue at a Pellegrini presser. Quite hilarious to see everyone scrambling around suddenly
k = 1
x= 1 , y = 0 , z = 0
x =0 , y = 1 , z = 0
x = 0 , y = 0 , = 1
k = 2
x= 1 , y = 1 , z = 0
x =0 , y = 1 , z = 1
x = 1 , y = 0 , = 1
k = 3
x= 1 , y = 1 , z = 3
x = 1 , y = 1 , z = 1
x = 1 , y = 0 , = 1
k = 4
x=∛3 , y = 1 , z = 0
x=∛2 , y = ∛2 , z = 0
x=∛2 , y = 1 , z = 1