FA Cup Qtr final draw - away (big shock) at Middlesbrough

Mathematically it is looked at as one incident as the probability resets after every event.

I get your point but in this example where there are only two outcomes it is this law that is applied.

Bending mathematical laws to suit agendas is forbidden :-)
Probability isn’t reset, that’s why bookies give better odds for tricasts etc, as, despite the fact they're individual races, the odds on the punter getting it right on 3 consecutive occasions, gets harder (the odds get bigger), that’s why 128-1 is correct, it’s not evens.
 
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I believe this is apt for Rammy Blue.
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Probability isn’t reset, that’s why bookies give better odds for tricasts etc, as, despite the fact they're individual races, the odds on the punter getting it right on 3 consecutive occasions, gets harder (the odds get bigger), that’s why 128-1 is correct, it’s not evens.

It is reset on these type of events.

Theoretically if you were betting in Jan 16 about us getting 7 aways on the run then you are correct. But the odds of getting Boro away rather than home was evens.

Choosing 2 horses In a double on a Saturday before both races are run and both horses are evens is 3-1.

Choosing the second horse after knowing the result of the first race, the odds are evens.

Depends which way you look at it.

The outcome of a draw in football is independent of the draw before it. Pretty much like the toss of a coin.
 
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