SkyBlueFlux
Well-Known Member
SWP's back said:The Earth is sufficiently flat for that to not be the case for most weapons though. Espcially when firing indoors on a flat surface, a la:blueish swede said:The earth surface is curved, irrespective of altitude. A shot fired horizontally is actually fired at a tangent to the curved surface. The distance the fired bullet has to fall is slightly greater than the original height because of this and therefore it takes slightly longer to reach the surface. The dropped bullet lands first.
[youtube]http://www.youtube.com/watch?v=D9wQVIEdKh8[/youtube]
Although admittedly I haven't watched the above clip yet, I've actually just taken the time to calculate myself how much of a difference the curvature of the Earth would generally make (anything to get away from exam revision) and although it would obviously vary I've come up with the following:
If the bullet were to drop from rest for approximately one whole second, it would generally fall about 4.9m (ignoring air resistance).
So let's say you start from a position which is 4.9m off the ground. The bullet travels at a standard 680mph horizontally, then the difference in the height dropped by the horizontal travelling bullet and the stationary dropped bullet, solely due to the curvature of the Earth, is roughly 8mm.
That extra 8mm would prolong the free-fall by approximately 0.0028s or 2.8ms.
This is with a gun fired at a height off the ground which is twice your average man's height.
The thing is, as with all physics, it's about how well these things can be approximated to a real system. In reality there's a fuckton of stuff out there which can effect the way these bullets travel. Air currents, the rotation of the earth, hell, even the malleability of the metal that the bullet is made from will have some kind of effect. You can't take them all into account as that would take forever.
For all intents, the two bullets will land nearly at exactly same time and for most practical purposes you can say that with confidence.