erm, i dunno, anyone?Abe Frohman said:It's 25 yrs since I tried anything like this but here goes
2a(squared)b(times)3a(cubed)b(squared)
must equal ((2 x (a x a)) x b) x (3 x (a x a x a) x (b x b) ?
Am i on the right track?
keemcfc said:erm, i dunno, anyone?Abe Frohman said:It's 25 yrs since I tried anything like this but here goes
2a(squared)b(times)3a(cubed)b(squared)
must equal ((2 x (a x a)) x b) x (3 x (a x a x a) x (b x b) ?
Am i on the right track?
thats what ive been doing, but im getting too much shit for it now, i just cant do it.de niro said:fuck it off, i did.
erm...hu?squirtyflower said:its
6 x a (to the power of 5) x b (to the power of 3)
thanks, but, i dont get it...Nyull said:All you need to do is multiply the numbers infront of the a or bs and then add up the powers
for example
2ab * 4a²b
First you multiply the 2 by the 4 giving 8.
Then a by a² is a³
And b by b is b²
which all together gives 8a³b²
for the one with the minus sign you have to factorise which means take common terms from each and put them outside brackes
eg
8ab² - 4ab
they're both divisible by 4,a and b so you take that outside and see what's left
8ab² divided by 4ab = 2b and 4ab divided by 4ab = 1
so your answer is 4ab(2b-1)
with the division do the topline first and then cancel common terms in the top and bottom line.
Hope that helps.
I'll check your answers if you'd like
=)