Russian invasion of Ukraine

[Citizen of Legoland]

Arnie for President.

Too young?

 

[SPIDERBOY]

The world has missed a trick not to fire a rocket at that stadium putin is talking from if it really is live and not old

99% of the people in there,will of probably been driven by bus from factories etc.
Probably told to applaud,cheer etc whilst en route.

Or maybe those who were arrested for protesting.

 

[GaudinoMotors]

I hope all these Russian "Celebs" appearing at this nazi style rally are going to be sanctioned, blacklisted and prevented from travelling.

 

[metalblue]

you mean day+month+year = 68 has occurred 534 times since 1900? if so:

121 years x 365 days = 44165, which means 68 is the result 0.012% of times. So for the result to be 68 for 3 specific and related events, wouldn't that be 0.012 * 0.012 * 0.012 = 0.000001728% chance of it happening?

I accept my probabilities math understanding may be flawed as its 40 years+ since I last used it.....

<edit> given the first "68" is arbitrary, it could have been any number, I guess the question then becomes what are the chances of events 2 and 3 being the same, which does significantly improve things 0.012 * 0.012 = 0.000144% chance, so whats that? about 1 in a million?

It is not evenly distributed. It didn’t occur at all between 1900 and 1905, 1906 it occurred once. By 1914 it was occurring 8 times a year, and it occurred on average nearly monthly every year between 1915 and 1939. It then didn’t occur at all between 1948 until 2005. In 2005 it occurred once and from 2014 is occurring about once a month on average again.

So the odds of them randomly picking 68 for WW2 and invasion of Ukraine was about 1 in 30, give or take, based on the year they choose.

 

[BlueAnorak]

So does arithmetic...
;-)

Eŕrr no I just copied the number incorrecty.
19+14+07+28 =68

 

[BlueAnorak]

It is not evenly distributed. It didn’t occur at all between 1900 and 1905, 1906 it occurred once. By 1914 it was occurring 8 times a year, and it occurred on average nearly monthly every year between 1915 and 1939. It then didn’t occur at all between 1948 until 2005. In 2005 it occurred once and from 2014 is occurring about once a month on average again.

So the odds of them randomly picking 68 for WW2 and invasion of Ukraine was about 1 in 30, give or take, based on the year they choose.

Glad to see someone else would do the same sort of search I was going to do after work. Now I don't need to bother. :-D

 

[BlueAnorak]

Now if Zelensky was a **** like Putin he would have seen this pro-Russian invasion concert as an invitation to fire a cruise missile into the stadium. They were probably all bribed to go in.

It's all a bit post 1933 Nuremburg isn't it.

 

[flook]

It is not evenly distributed. It didn’t occur at all between 1900 and 1905, 1906 it occurred once. By 1914 it was occurring 8 times a year, and it occurred on average nearly monthly every year between 1915 and 1939. It then didn’t occur at all between 1948 until 2005. In 2005 it occurred once and from 2014 is occurring about once a month on average again.

So the odds of them randomly picking 68 for WW2 and invasion of Ukraine was about 1 in 30, give or take, based on the year they choose.

I'm impressed by the level of your research

however, random picking didn't actually happen, these are dates of events obviously, so whether the probabilities are grouped at the time of the event is (I think?) largely irrelevant

I do know for sure that I'm spending far too much time thinking about this

 

[bluemanchester]

We will probably get it on the never never from them.

It is not evenly distributed. It didn’t occur at all between 1900 and 1905, 1906 it occurred once. By 1914 it was occurring 8 times a year, and it occurred on average nearly monthly every year between 1915 and 1939. It then didn’t occur at all between 1948 until 2005. In 2005 it occurred once and from 2014 is occurring about once a month on average again.

So the odds of them randomly picking 68 for WW2 and invasion of Ukraine was about 1 in 30, give or take, based on the year they choose.

you mean day+month+year = 68 has occurred 534 times since 1900? if so:

121 years x 365 days = 44165, which means 68 is the result 0.012% of times. So for the result to be 68 for 3 specific and related events, wouldn't that be 0.012 * 0.012 * 0.012 = 0.000001728% chance of it happening?

I accept my probabilities math understanding may be flawed as its 40 years+ since I last used it.....

<edit> given the first "68" is arbitrary, it could have been any number, I guess the question then becomes what are the chances of events 2 and 3 being the same, which does significantly improve things 0.012 * 0.012 = 0.000144% chance, so whats that? about 1 in a million?

And they say accountants are boring ;-)

 

[metalblue]

Glad to see someone else would do the same sort of search I was going to do after work. Now I don't need to bother. :-D

I’ve got it on an excel spreadsheet now mate. Shits got real ;)