There are infinite solutions, based on moving the inner square around.View attachment 115691
Is that allowed? (oh read the question wrong, flip the shading/unshading)
That's what I initially thought of. But then I thought... how would I actually go about accurately shading the perimeter of the inner square? Which led me to think about, perhaps folding the larger square in half or perhaps along the diagonals to assist in shading... Hmm... Which then led me to think about each of the 4 sub-squares. How do I go about shading exactly the right amount of each of them... hang on, the right amount is 1/2! And bingo!View attachment 115691
Is that allowed? (oh read the question wrong, flip the shading/unshading)
Genius.That's what I initially thought of. But then I thought... how would I actually go about accurately shading the perimeter of the inner square? Which led me to think about, perhaps folding the larger square in half or perhaps along the diagonals to assist in shading... Hmm... Which then led me to think about each of the 4 sub-squares. How do I go about shading exactly the right amount of each of them... hang on, the right amount is 1/2! And bingo!
I'm now ready for 5th-grade maths! LOL.Genius.